🇨🇩 Analytic geometry and matrices

Descriptive geometry: intersections and polyhedra

⏱ 30 minOfficial programme: CD-H3-GEO-03

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🎯 In this lesson, you will learn to

  • Construct plane intersections and represent polyhedra and plane sections.

The lesson

Introduction

Before building a warehouse in Kisangani, the architect draws the building on a flat sheet. How can an object in space be represented exactly on a plane, and how can lengths, intersections and sections be read from the drawing? That is the purpose of descriptive geometry: the object is projected onto two perpendicular planes and we work on the resulting drawing, called the two-view drawing.

Explanation

Projections and the two-view drawing

We use a horizontal plane π\pi and a frontal (vertical) plane π′\pi', which meet along the ground line, also called the hinge line (chch). A point AA in space has:

  • a horizontal projection aa (on π\pi) and a frontal projection a′a' (on π′\pi');
  • a height: its distance to the horizontal plane;
  • a depth: its distance to the frontal plane.

To obtain the two-view drawing, π\pi is rotated about the hinge line until it lies in the plane of π′\pi'. Then aa and a′a' lie on the same perpendicular to chch (the reference line): for a point in front of π′\pi' and above π\pi, a′a' is above chch at a distance equal to the height, and aa is below it at a distance equal to the depth.

Explanation

Lines, planes and intersections

  • The traces of a line are its intersection points with π\pi (horizontal trace, height zero) and with π′\pi' (frontal trace, depth zero).
  • A general plane is often given by its traces: its lines of intersection with π\pi and with π′\pi'; they meet on the hinge line.
  • Intersection of two planes: it is a line. It passes through the common point of the two horizontal traces and through the common point of the two frontal traces.
  • Line and plane: a line is parallel to a plane if it is parallel to a line of that plane. Otherwise it pierces the plane at one point, found by cutting the plane with an auxiliary plane containing the line.
  • Two lines in space are intersecting, parallel or skew (not coplanar): they intersect if their crossing points in the horizontal view and in the frontal view lie on the same reference line.

Explanation

Polyhedra and plane sections

A polyhedron is a solid bounded by polygonal faces (cube, prism, pyramid…). For a convex polyhedron, Euler’s relation links the number of vertices SS, edges AA and faces FF:
S−A+F=2.S-A+F=2.
The section of a polyhedron by a plane is a polygon each of whose sides is the segment common to the plane and to a face. Method: find the points where the plane cuts the edges, then join them face by face.

  • A plane parallel to the bases of a prism gives a section congruent to the bases.
  • A plane parallel to the base of a pyramid, at distance dd from the apex (height hh), gives a polygon similar to the base with ratio k=dhk=\dfrac dh; its area is k2k^2 times the area of the base.
  • A section of a cube has at most 66 sides, since the cube has 66 faces.

Worked example

Problem: A point is located by (x,y,z)(x, y, z): xx along the hinge line, yy the depth, zz the height. Find the traces of the line through A(0,1,4)A(0, 1, 4) and B(3,4,1)B(3, 4, 1).

Step 1: A point of (AB)(AB) is M=A+t AB→=(3t,1+3t,4−3t)M=A+t\,\overrightarrow{AB}=(3t, 1+3t, 4-3t).

Step 2: Horizontal trace: height zero, 4−3t=04-3t=0, so t=43t=\dfrac43 and H(4,5,0)H(4, 5, 0).

Step 3: Frontal trace: depth zero, 1+3t=01+3t=0, so t=−13t=-\dfrac13 and V(−1,0,5)V(-1, 0, 5).

Answer: H(4,5,0)H(4, 5, 0), with depth 55; V(−1,0,5)V(-1, 0, 5), with height 55.

Worked example

Problem: A pyramid of height 1212 cm has a square base with side 99 cm. It is cut by a plane parallel to the base, 88 cm from the apex. What is the area of the section?

Step 1: The section is a square similar to the base, with ratio k=812=23k=\dfrac{8}{12}=\dfrac23.

Step 2: Its side measures 9×23=69\times\dfrac23=6 cm.

Step 3: Its area is 62=366^2=36 cm²; we check k2×81=49×81=36k^2\times81=\dfrac49\times81=36.

Answer: 3636 cm².

Watch out

Watch out: In the two-view drawing, the distance between aa and a′a' is not the height of the point: for a point in front of π′\pi' and above π\pi, it equals height + depth. And a plane section is not drawn by joining any points: two points of the section are joined only if they lie on the same face.

Key points

  • A point: projections aa and a′a' on the same reference line; height (above chch) and depth (below).
  • Traces of a line: height zero (horizontal), depth zero (frontal).
  • Intersection of two planes: the line through the common points of their traces of the same kind.
  • Euler: S−A+F=2S-A+F=2 for a convex polyhedron.
  • Section of a pyramid parallel to the base: ratio k=dhk=\dfrac dh, area multiplied by k2k^2.

✍️ Exercises

Answer one exercise at a time. Your answer is checked right away, with an explanation.

Exercise 1 of 9

★ Easy

A point AA lies in front of the frontal plane and above the horizontal plane; its height is 33 cm and its depth 22 cm. In the two-view drawing, what is the distance between its projections aa and a′a'?

cm

You can use a decimal comma or point (2,5 or 2.5).