🇨🇩 Algebra: integers, decimals, fractions

Proportionality, percentage and scale

⏱ 25 minOfficial programme: CD-E7-ALG-03

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🎯 In this lesson, you will learn to

  • Use ratios, proportions, percentages and scale in problems.

The lesson

Introduction

Masika sews uniforms in Bukavu. If 66 m of fabric cost 27 00027\,000 FC, how much do 1010 m cost? How much is a 15 %15\,\% discount on a uniform? And on a map, how many kilometres do 7.57.5 cm stand for? These three questions use the same idea: proportionality. In this lesson you learn to use ratios, proportions, percentages and scales.

Explanation

Ratios and proportions

The ratio of aa to bb (b≠0b\ne0) is the quotient ab\dfrac{a}{b}.

A proportion is an equality of two ratios: ab=cd\dfrac{a}{b}=\dfrac{c}{d}. The terms aa and dd are the extremes, bb and cc the means. Key property:
ab=cd  ⟺  a×d=b×c\frac{a}{b}=\frac{c}{d}\iff a\times d=b\times c
(the product of the extremes equals the product of the means).

Two quantities are proportional if you always go from one to the other by multiplying by the same number kk, the proportionality coefficient. To find an unknown value, use the rule of three: first compute the value for one unit.

Explanation

Percentages

A percentage is a ratio with denominator 100100: p %=p100p\,\%=\dfrac{p}{100}.

  • Taking p %p\,\% of a quantity AA: p100×A\dfrac{p}{100}\times A. Example: 15 %15\,\% of 32 00032\,000 FC is 0.15×32 000=4 8000.15\times32\,000=4\,800 FC.
  • Increasing AA by p %p\,\%: new value A×(1+p100)A\times\left(1+\dfrac{p}{100}\right).
  • Decreasing AA by p %p\,\%: new value A×(1−p100)A\times\left(1-\dfrac{p}{100}\right).
  • Finding a percentage: partwhole×100\dfrac{\text{part}}{\text{whole}}\times100.

Explanation

Scale

On a map or a plan, the scale is the ratio
scale=distance on the mapreal distance\text{scale}=\frac{\text{distance on the map}}{\text{real distance}}
with both distances expressed in the same unit.

A scale of 150 000\dfrac{1}{50\,000} means that 11 cm on the map stands for 50 00050\,000 cm, that is 500500 m, in reality.

  • Real distance == map distance ×\times 50 00050\,000.
  • Map distance == real distance ÷\div 50 00050\,000.

Worked example

Problem: 66 m of fabric cost 27 00027\,000 FC. How much do 1010 m of the same fabric cost?

Step 1: Price of one metre: 27 000÷6=4 50027\,000\div6=4\,500 FC.

Step 2: Price of 1010 m: 10×4 500=45 00010\times4\,500=45\,000 FC.

Step 3: Check with the proportion: 627 000=1045 000\dfrac{6}{27\,000}=\dfrac{10}{45\,000} because 6×45 000=270 000=27 000×106\times45\,000=270\,000=27\,000\times10.

Answer: 1010 m cost 45 00045\,000 FC.

Worked example

Problem: A uniform costs 32 00032\,000 FC. The tailor gives a 15 %15\,\% discount. What is the new price? Then, in a class of 4040 pupils, 1818 are girls: what percentage is that?

Step 1: Discount: 15100×32 000=4 800\dfrac{15}{100}\times32\,000=4\,800 FC.

Step 2: New price: 32 000−4 800=27 20032\,000-4\,800=27\,200 FC (or 32 000×0.85=27 20032\,000\times0.85=27\,200 FC).

Step 3: Percentage of girls: 1840×100=45\dfrac{18}{40}\times100=45.

Answer: the uniform costs 27 20027\,200 FC; girls make up 45 %45\,\% of the class.

Worked example

Problem: On a map with scale 1200 000\dfrac{1}{200\,000}, two villages are 7.57.5 cm apart. What is the real distance in kilometres?

Step 1: Real distance in centimetres: 7.5×200 000=1 500 0007.5\times200\,000=1\,500\,000 cm.

Step 2: Conversion: 11 km =100 000=100\,000 cm, so 1 500 000÷100 000=151\,500\,000\div100\,000=15.

Answer: the two villages are 1515 km apart.

Watch out

Watch out: a 10 %10\,\% rise followed by a 10 %10\,\% fall does not bring you back to the starting price, because the fall is computed on the new price. With 10 00010\,000 FC: 10 000×1.1=11 00010\,000\times1.1=11\,000 FC, then 11 000×0.9=9 90011\,000\times0.9=9\,900 FC. For a scale, always convert both distances to the same unit before computing.

Key points

  • Proportion: ab=cd  ⟺  a×d=b×c\dfrac{a}{b}=\dfrac{c}{d}\iff a\times d=b\times c.
  • Rule of three: go through the value for one unit.
  • p %p\,\% of AA: p100×A\dfrac{p}{100}\times A; rise: ×(1+p100)\times\left(1+\dfrac{p}{100}\right); fall: ×(1−p100)\times\left(1-\dfrac{p}{100}\right).
  • Scale == map distance ÷\div real distance, in the same unit.

✍️ Exercises

Answer one exercise at a time. Your answer is checked right away, with an explanation.

Exercise 1 of 8

★ Easy

Compute 25 %25\,\% of 48 00048\,000 FC.

FC

You can use a decimal comma or point (2,5 or 2.5).